![]() php files: grep -color -R -include='*.php' 'eval('. My final command for searching eval() in. This way you will exclude binary files, images that will make your search faster and easy for you to find what you are looking for.īONUS: You can add –color in the grep command so it will be easier to spot the word sh you can use the following command: grep -R -include='*.' 'your word' /path/for/searching If you need this grep to search for multiple extensions such as. My usual recursive grep command when I am IN the directory I want to search: cd /path/for/searching/ My grep command is: grep -R -include='*.php' 'text pattern' /path/for/searching/ Grep recursively for “some pattern” in PHP files js files and sometimes I search base64 which can be in a lot of. So here is my way of searching the hack patterns such as eval, base64_decode etc which are also included in. Make sure to understand the section REGULAR EXPRESSIONS of the grep manual page. Lately I’ve been cleaning a lot of WordPress websites from malware code, and the simple way for me was to use grep recursive search to find certain patterns in uploaded. Also, be aware that the grep tool uses a pattern for the search string. You can use this with any Linux glob characters, such as wildcards to match everything including a certain extension: grep -inr -include. If its specified, grep will treat all include flags as a whitelist. Scanning all C++ files under current directory awk -v wordsListFile=nameSpacesListFile.txt -f script.awk $(find. The -include flag tells grep to only include files matching a certain pattern. WordsListCount = split(wordsListStr, wordsListArr, "\n") # split wordsListStr by newLine into array wordsListArr, saved array length into wordsListCountįor (currWord in wordsListArr) wordsMatchArr = 0 # reset array wordsMatchArr to 0 Getline wordsListStr < wordsListFile # read wordsListFile as single string wordsListStr script.awk BEGIN # set record seperator to something unlikely matched, causing each file to be read entirely as a single record Print file name only if all words matched. Scanning each file once for all the words (read each file as a single record). I suggest to use gawk (standard Linux awk) script. Files pass the filter if they contain at least one instance of each word. Surely there is a way to do this? This is essentially a filtering problem: Take all the files found (recursively) inside a directory, and apply a filter to them for each of the words in the input list.
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